How to calculate the weight of hollow rectangular steel section?/Calculating the weight of mild steel rectangular hollow tube.

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For the calculation procedure, go through the following steps.👇

Let us consider a hollow rectangular mild steel tube or pipe of dimension 70mm × 40mm.× 3mm. as shown in the fig. below. Let us calculate the weight for the pipe having a 3-meter length.

Hollow rectangular steel section.

Here, thickness T = 3mm.  breadth B = 70mm, depth D = 40mm., and length L =3m.

Hollow rectangular MS tube.

First, we will calculate the sectional area in two parts, the orange-colored part area as A1, and green colored part area as A2.

Area A1 = [Breadth( B) × Thickness (T) × 2nos. ]

               = [70mm × 3mm. × 2nos.]

 By converting mm. unit into meters, we get 

             

             = [0.07 × 0.003 × 2 ]

          A1 = 0.00042 sqm.

Area A2  = [{D - ( 2 × T )} × T × 2 nos.]

               = [ {40 - ( 2  × 3)}  × 3  × 2 nos.]

                = [ 34 mm. × 3mm. ×2nos.]

By converting mm. unit into meters, we get 

               = [ 0.034m. × 0.003m. × 2nos.]

         A2 = 0.000204 sqm.

Now, total sectional area

                   A = [A1 +A2]

                      = [0.00042 +0.000204]

                   A= 0.000624 sqm.

As you know, 

   volume = [ area × length ]

                = [A  × L ]

                = [ 0.000624 × 3]

            V =  0.001872 cum.

The density of mild steel is 7850 kg./cu.m.

So, the weight of the hollow rectangular MS pipe

                              = [volume × density]

                              = [0.001872 × 7850]

                              =  14.695kg.

The weight of the rectangular steel section/meter.

       = [14.695kg ÷ 3m.]

       = 4.8983 kg./m.

       = 1.493 kg / ft.

        (As 1m = 3.28084 ft.)

For you 👇

❤ How to calculate the weight of the MS sheet?/ Easy method to calculate the weight of MS sheets of all dimensions.

          Alternate method:

First, we will calculate the total area inclusive of the hollow part, and then we will deduct the inner hollow portion (shown in green color) of the pipe.

Area a1   =[ B × D]

               = [70mm. × 40mm.] 

 By converting mm. unit into meters, we get            

         a1 = [0.07 × 0.04]

         a1 = 0.0028 sqm.

          

Area a2  = [{ B - (2T)} × { D - ( 2T)}]

              =  [{ 70 -( 2 × 3)} × { 40 - (2 × 3)}]

               = [ 64mm.× 34 mm.]

              ( i.e. inner green hollow part )

By converting mm. unit into meters, we get 

               = [0.064m.  ×0.034m.]

             a2 = 0.002176 sqm.

Now, the total sectional area

             A = [a1 - a2]

               = [0.0028 - 0.002176]

            A = 0.000624 sqm.

Note: We got the same area (A ) as calculated before.

Volume = [area  × length]

              = [0.000624 ×3]

         V =  0.001872 cum.

So, the weight of the hollow rectangular MS pipe

                              = [volume × density]

                              = [0.001872 × 7850]

                              = 14.695 kg.

PART2 👈Back

Thank you for going through this calculation😃. 

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