Let us consider a 1 cum. of plastering mortar in a 1:4 ratio
The wet volume of the mortar = 1 cum.
Dry volume of the plaster mortar
= 1.33 × 1 cum.
= 1.33 cum.
The volume of cement required
= [dry volume of plaster mortar × (ratio of cement ÷ total ratio)]
= [1.33 cum × ( 1 ÷ (1+4 ))]
= [1.33 × 0.2]
= 0.266 cum.
= 9.393 cu ft.
As you know, the density of cement = 1440kg/cum.
So, the total quantity of cement required in kgs.
= [0.266 × 1440]
= 383.04 kg
One bag of cement weighs 50kg
The number of cement bags required
= [383.04 ÷ 50]
= 7.66 bags.
The volume of sand required
= [dry volume of plaster mortar × (ratio of sand ÷ total ratio)]
= [1.33 cum × ( 4 ÷ (1+4 ))]
= [1.33 × 0.8]
= 1.064 cum.
= 37.575 cu.ft.
( 1cu.m = 35.315 cu.ft. )
or
Volume of sand
= volume of cement × 4
= [0.266 cum.× 4]
= 1.064 cum.
or
Volume of sand
= [total dry volume- the volume of cement]
= [1.33 cum - 0.266 cum]
=1.064 cum.
Density of dry sand = 1602 kg/cum.
Weight of sand required
= [1.064 cum × 1602 kg/cum]
= 1704.528 kg.
Quantity of water required
= [weight of cement × w/c ratio]
= [383.04kg × 0.6 ]
= 229.82 kg i.e. 229.82 liter.
Note: Water is mixed depending upon the consistency required for the plastering. If you use plasticizers the requirement for water reduces.
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Now we will consider plaster mortar in a 1:6 ratio.
The volume of cement required
= 1.33 cum × ( 1 ÷ (1+6 ))
= 1.33 × 0.14285
= 0.19 cum.
= 6.709 cu ft.
The total quantity of cement required in kgs.
= 0.19 × 1440
= 273.6 kg
One bag of cement weighs 50kg
The number of cement bags required
= 273.6 ÷ 50
= 5.472 bags.
Volume of sand
= volume of cement × 6
= 0.19 cum.× 6
= 1.14 cum.
Weight of the sand
= 1.14 cum. × 1602 kg /cum.
= 1826.28 kg.
To get the quantity of materials for 1 cu ft. of plastering mortar, you have to replace the unit cum. from cu ft.
2 1: 6 0.19 1.14 0.155
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