# PARAM VISIONS

All about civil construction knowledge- PARAM VISIONS

### Calculating the quantity of materials in the RCC footings of a compound wall. / Estimating & costing of a compound wall ( part 3 ).

Let us make a footing of size 1.5 ft × 1.5 ft. having 10" ( 0.833 ft. ) thickness as shown in the drawing.

Given data :

Footing length = 1.5 ft.,

Width = 1.5 ft. ,

Thickness = 0.833 ft.

Rebar diameter = 10 mm.(0.0328 ft.),

Spacing =5" (0.416 ft. ) c/c,

Cover = 2"(0.166 ft ) on all the sides.

From part 1, the number of footings = 14nos.

4a. The volume of footing for the compound wall

= [total nos. × length × breadth × thickness]

= [14 nos. × 1.5 ft. × 1.5 ft. × 0.833 ft.]

=26.24 cu ft.i.e.0.743 cum.

4b. BBS for the footings:

No. of bars along the x-axis

= [ {( footing length ) - ( 2 × cover )} ÷ spacing ] + 1

= [ {( 1.5 ft.) - ( 2 ×0.166 ft.)} ÷ 0.416 ft.] +1

= [ { 1.168 ft. } ÷ 0.416 ft. ] +1

= 2.807 +1

= 4 nos.

( By rounding off )

No. of bars along the y-axis

= [ {( footing width ) - ( 2 × cover )} ÷ spacing ] + 1

= [ {( 1.5 ft.) - ( 2 ×0.166 ft.)} ÷ 0.416 ft.] +1

= [ { 1.168 ft. } ÷ 0.416 ft. ] +1

= 2.807 +1

= 4 nos.

( By rounding off )

Cutting length of the bar along the x-axis

=  [ {bar length in x-axis } +{ 2 nos. ×( L- bend length)}] - 2nos.× ( 2 times bar dia. for 90° bend.)

( we have deducted 2 times bar dia i.e. 2d for the  90° bend of the bar. )

=[ { footing length - 2 × cover } + 2nos.×{ footing height - 2 × cover}] - 2× ( 2 × bar dia. )

= [ { 1.5 ft. - 2 × 0.166 ft. } + 2 × { 0.833 ft. - 2 × 0.166 ft. } ] - 2 × ( 2 × 0.0328 ft.)

= [ 1.168 ft. + 1.002 ft. ] - 0.131ft.

= 2.17 ft. - 0.131 ft.

= 2.039 ft. i.e. 0.6214 m.

Cutting length of the bar along the y -axis

=  [ {bar length in y-axis } +{ 2 nos. ×( L- bend length)}] - 2nos.× ( 2 times bar dia. for 90° bend.)

=[ { footing width - 2 × cover } + 2nos.×{ footing height - 2 × cover}] - 2× ( 2 × bar dia. )

= [ { 1.5 ft. - 2 × 0.166 ft. } + 2 × { 0.833 ft. - 2 × 0.166 ft. } ] - 2 × ( 2 × 0.0328 ft.)

= [ 1.168 ft. + 1.002 ft. ] - 0.131ft.

= 2.17 ft. - 0.131 ft.

= 2.039 ft. i.e. 0.6214 m.

Note: The cutting length & number of bars in both ( x & y ) directions will be the same, in the case of square footing having a similar bar diameter.

Now, we will prepare BBS of the footing, from calculated data.

sl       bar      dia.   no.   length      total     weight         total
no.    type    mm.            in m.    length    in kg/m       weight

1.    x- axis    10    4    0.6214     2.4856     0.62         1.54

2.   y - axis   10     4     0.6214     2.4856      0.62         1.54

Total weight of the bars = 3.08kgs

Add 2 % wastage            = 0.0616kgs

A grand total of rebar for a footing    =  3.1416 kgs.

Note : Weight of 10mm dia bar /meter is 0.62 kg.

The total weight of the 10mm bar for all the footings

= [14 nos. × 3.1416 kgs.]

= 43.98 kgs.

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