All about civil construction knowledge- PARAM VISIONS

Calculating the area of irregular shaped land or plot or site./ Area calculation for the irregular shaped land.( part- 2 )

 If you are looking for a readymade calculator for type-4 land, then click here.

 For the calculation procedure, go through the following steps.👇


 Back 👈 Part-1 

Now, let us go through some of the possible irregular shapes of the land or plot, and let us calculate the area of those plots, by using mathematical formulas.

Type 3:

Here, side AD & side BC are parallel to each other having the same length.

Given data :

 Side AD (a ) = side BC =  10 m. 

   Side AB = side DC = 7m.

   Side AD & BC of the land are parallel to each other.

The perpendicular distance between the side AD & BC ( h ) = 6m.


The area of the land is calculated by the formula

= [ a × h]

= [side AD or side BC  × Perpendicular distance]

= [10m × 6m]

 60 sqm.


Note:

1. The formula should be used only when the two sides of the land are parallel to each other having the same length.

2.  The perpendicular distance between the two parallel sides, i.e. h can be measured directly on-plot, if not known.


Type 4:

Here, all four sides of the land are unequal in length and are not parallel to each other.

Given data :

 Side AD  = 11m.

 Side BC =  10 m. 

  Side AB =7m.

 Side DC = 6.7m.

   All four sides are unequal and are not parallel to each other.


To calculate the area of land, we have to measure the distance AC as shown in the above drawing.

Side AC = 13.2m as measured on-site.

Now, we will calculate the area of triangle ABC & triangle ACD separately.

We will use Heron's formula to calculate the areas.


Area of triangle ABC

= √ s (s - a ) ( s - b ) ( s - c )

Here, s is the semi perimeter of the triangle 

i.e. s = a + b + c / 2

 a, b, and c are the 3 sides of the triangle.

By data input

s = [(side AB + side BC + side AC) / 2]

   = [(7m + 10m + 13.2 m) ÷ 2]

  =  [30.2 m ÷ 2]

  = 15.1m.


Area of triangle ABC

 = [√ 15.1 ( 15.1 - 7 ) ( 15.1 - 10 ) ( 15.1 - 13.2 )]

 = [√ 15.1 ( 8.1 ) ( 5.1 ) ( 1.9 )]

= [√ 1185.184]

=34.426 sqm.


Similarly, area of triangle ACD

= [√ s (s - a ) ( s - b ) ( s - c )]

s = [(side AD + side DC + side AC) / 2]

  = [(11m + 6.7m + 13.2 m) ÷2]

 =  [30.9 m.÷2]

 = 15.45 m.


Area of triangle ACD 

= [√  15.45 ( 15.45 - 11 ) ( 15.45 - 6.7 ) ( 15.45 - 13.2 )]

= [√ 15.45 × 4.45 × 8.75 × 2.25]

= [√ 1353.565]

= 36.79 sqm.


Area of the land ABCD 

 = [Area of triangle ABC + area of triangle ACD]

 = [34.426 sqm. + 36.79 sqm.]

  = 71.216 sqm.

          Back 👈 Part 1             Continued 👉 Part-3


Thank you for going through this calculation. Have a good day😄








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