Let us consider an MS square bar of size 20mm × 20mm having 3m. length.

**Given data:**

**Calculation:**

The weight of the MS square bar is calculated by the formula,

= **[d2L / 127.39]**

Here,

d = 20mm. & L = 3m.

Weight of the bar

= [20mm × 20mm ×3m / 127.39]

= **9.42 kg**.

**Note**: In this formula, the sectional dimension should be in millimeters & the length should be in meters.

MS square bar. |

So, you can calculate the weight of the MS square bars of any dimension by using this formula.

Now the question is,

#### How the formula d2L / 127.39 is derived for the MS square bar?

Let us consider a square bar of sectional dimension** d** in mm having the length** L** as shown below.

As you know, in square bars, all 4 cross-sectional sides are equal.

The volume of the MS square bar

= [breadth × depth × length]

= [(d × 0.001) m. × ( d × 0.001) m. × L m.]

(1mm = 0.001m. and we have converted all dimensions into the same unit i.e. meter.)

= 0.000001 d2L cum.

Now,

the weight of the MS bar

= [volume × density]

= [0.000001 d2L cum × 7850 kg/ cum]

= **0.00785 d2L** kg

OR

By inverse,

Weight of the MS square bar

=** d2L / 127.39 kg.**

**To go through the articles on Estimation & calculation in civil engineering,** **click here.**

**Thank you for going through this article❤. Have a good dayðŸ˜„**

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