All about civil construction knowledge- PARAM VISIONS

Calculating the volume of concrete in a triangular pile cap having 3-piles.

 Let us calculate the volume of concrete in a triangular pile foundation having 3 nos. of the pile, as shown below.



Given data:

Pile diameter = 0.6m.( d )

No. of piles = 3 nos.

Length of pile = 16m. (h )

Depth of the pile cap = 0.9m.(D )


The volume of concrete in the piles

= 3nos.× πr2 h

Here,

r = radius of the pile.

= d ÷ 2

= 0.6m ÷ 2

= 0.3m.

h = length of the pile.


The volume of concrete in piles

= 3nos. × 3.142 × (0.3m)2 × 16m.

13.57 cum.


The volume of concrete in the pile cap :

The volume of  pile cap concrete

=  Surface area (A ) × depth ( D )

First, let us calculate the sectional area (A1) of rectangle ABCD, as shown in the below drawing.

Area of rectangle ABCD (A1)

    =L × B

    = 2.2m × 2.0m

    = 4.4 sqm.

To get the surface area ( A) of the pile cap, we have to deduct the area of triangles AEF & GDH from the rectangle area.

Here,

 Triangle AEF = triangle GDH 

Area of triangle AEF 

= 0.5 × base × height.

= 0.5 × side AE × side AF

Side AE 

= [ ( 1/2 ×side BC ) - (1/2 × side EG )]

=  [ ( 1/2 ×2m. ) - (1/2 × 0.6m. )]

= [ 1m - 0.3 m ]

= 0.7m.


Side AF 

= side AB - side FB

= 2.2m - 0.7m

= 1.5m.


I have redrawn the triangle, with the calculated length of the sides AF & AE as shown below.

Area of triangle AEF

 = 0.5 × side AE × side AF

= 0.5 × 0.7m × 1.5m.

= 0.525 sqm.


 The surface area of the pile cap (A )

= [area of rectangle ABCD - (2nos. × area of a triangle AEF )]

= [4.4 sqm. - (2nos. × 0.525sqm.)]

= [4.4 sqm. - 1.05 sqm.]

= 3.35 sqm.


Now, the concrete vol. of pile cap

= surface area (A ) × depth (D )

= 3.35 sqm. × 0.9m.

= 3.015 cum.


The total concrete volume of 3-pile foundation

= The vol. of concrete in pile cap + total vol. of concrete in piles.

= 3.015 cum + 13.57 cum.

 16.585 cum.

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