All about civil construction knowledge- PARAM VISIONS

How to design a square water tank?/ How to calculate the dimensions of square water tank?

 Let us design a square water tank for a factory building having 25 workers as shown below.




According to BIS standard IS 1172-1993,  the average water consumption per head for a factory having bathrooms are ( India ) 45 liters/ day.




The volume of water required ( in liters ) per day for 25 workers

   = [ per capita consumption /day × no. of workers.]

   = [ 45 liters × 25 nos.]

   = 1125 liters.


Now, let us build a water tank having 2ft. depth as shown below.




Given data:

Depth D = 2 ft.

As we are constructing a square tank, the length will be equal to the breadth.

i.e. L = B


A. Method - 1:

As you know, 

The volume of the water tank

V1 = [ length (L) × breadth (B) × depth ( D ) ]

      = [ L × B × 2 ft. ]

Here, the volume of the water tank is equal to the vol. of water consumed/day. Let us add 15% extra in the tank volume for the sump & emergency needs.

So, the required volume ( V ) 

 = [water consumption/day + 15% of daily consumption]

 = [ 1125 liters + {( 15 ÷ 100) × 1125 liters}]

= [ 1125 liters. + 168.75 liters ]

1293.75 liters.


As you know, 

  1 cu ft. = 28.3168 liters

  So, the vol. V of the water tank in cu ft.

   = [ 1293.75 ÷ 28.3168 ] cu ft.

   = 45.688 cu ft.


Now,    

   V =  [( L × B) × 2 ft. ]

 45.688 cu ft. = [ ( L × L )× 2 ft. ]

By cross multiplication,

    ( L × L ) = [45.688 cu ft. ÷ 2 ft.]

          L2    = 22.844 sq ft.

              L = √22.844

                 = 4.779 ft.


The dimension of the water tank for holding water/ day

     = L × B × H 

     = 4.779 ft. × 4.779 ft. × 2 ft.



Note :

If you want to store the water for the 2days requirement, then you have to double the value of  L2  or recalculate for the 2 days water consumption.

For Eg., Let us take 2 times the  L2   to double the vol. of the tank.

 L2    = 22.844 sq ft. { as calculated}

Making  L2  into 2 times

            L2   = [2 × 22.844]

                   = 45.688 sq ft. 

            L    =  √45.688

                   = 6.759 ft.


Now, the vol. of a square tank

               = L × B × H 

               = [ 6.759 ft. × 6.759 ft. × 2 ft.]

              = 91.36 cu ft. ( i.e. double the capacity of 45.688 cu ft.)


B. Method-2:

Let us assume the ideal required dimensions of the square tank is as shown in the drawing.


Given data:


   Depth = D ft.

As we are constructing a square tank, the length will be equal to the breadth.

i.e. L = B

Length L = breadth B = 2 × depth = 2D

  The required vol. of water tank 

    = 45.688 cu ft. (as calculated above. )


Now,

                 V =  [ L × B × D]

   45.688 cu ft. = [ ( 2D ) × ( 2D) × D ]

  45.688 cu ft. = [ 4 × D3  ]

    D3

        = [45.688 cu ft. ÷ 4]
        
        = 11.422 cu ft.

   D = [∛  11.422 cu ft.]

       = 2.252 ft.


  Length = 2D = [2 × 2.252 ft.]

                        = 4.504 ft.


Breadth = length = 4.504 ft.

The dimension of the square water tank for holding water/ day

  = L × B × H 




     = 4.504 ft. × 4.504ft. × 2.252 ft.

To go through all types of structural design articles, click here.

Thank you for going through this article. Have a good day 😄.




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