How to convert reduced bearing to whole circle bearing?/ Converting RB to WCB in surveying.

 Let us consider 4 lines in all 4 quadrants having reduced bearing as given below.

Line	RB
AB	N55°15'E
BC	S27°45'E
CD	S42°0'W
DE	N34°30'W

 

Let us convert the given RB into WCB.

Note: 

          WCB 👉 short form of whole circle bearing.

             RB 👉  short form of reduced bearing.

1. Line AB:

The given RB is N55°15'E which lies in the 1st quadrant.

Here, WCB= θ1 = RB = 55°15'

 2. Line BC:

As you can observe in the above drawing, the given RB i.e. S27°45'E  lies in the second quadrant.

WCB = θ2 =  [180° - RB]

                  = [180° - 27°45']

                  = 152°15'

3. Line CD:

The given RB is S42°W, which lies in the third quadrant.

WCB = θ3 =  [180° + RB]

                  = [180° + 42°]

                  = 222°

4. Line DE:

The given RB is N34°30'W, which lies in the fourth quadrant.

WCB = θ4 =  [360° - RB]

                  = [360° - 34°30']

                  = 325°30'

To understand A to Z of surveying, click here.

Thank you for going through these calculation steps❤. Have a good day 😄.

Share: