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Calculating volume of coping & backfilling for a compound wall. / Estimating & costing of a compound wall ( part 7 ).

 BACK πŸ‘ˆ PART 6  

Let us make coping over block masonry having 4" (0.33 ft.) thickness in M15 grade.



8. The volume of coping for the compound wall

= coping length × width × thickness

= block masonry length × masonry width × coping thickness

= 119.5 ft. × 0.5 ft. × 0.33 ft.

= 19.717 cu ft. i.e. 0.558 cu m.


Let us make this coping in M15 grade concrete.

The no. of cement bags required for the coping work

=17.942 bags × (19.717 ÷ 100 cu ft. )

= 3.537 bags.

The volume of sand required for coping

= 44 cu ft × (19.717 ÷ 100 cu ft. )

= 8.675 cu ft.

The volume of coarse aggregates required

= 88 cu ft. × (19.717 ÷ 100 cu ft. )

= 17.35 cu ft.

Note: The above value for the calculation purpose is taken from " Calculating the quantity of materials in 100 cu ft. & 1 cum. of M15 (1:2:4 ) grade concrete".


9. The volume of backfilling for the compound wall

Backfilling for plinth beam

= Volume of excavation for plinth beam. - beam PCC volume - plinth beam volume up to GL.


= [(145.365 cu ft.) - (52.33 cu ft.) - (97.125cu ft. × 0.583ft ÷ 1 ft.) 

                                    ( By volume ratio with plinth beam πŸ‘†)

= 145.365 cu ft. - 52.33 cu ft - 56.623 cu ft.

= 36.412 cu ft.


Backfilling for footing.



=[ volume of excavation for footing - {footing vol. - soling vol. - PCC vol. - column vol. up to GL.}]

= [140 cu ft.- {26.24 cu ft. + 42 cu ft. + 18.48 cu ft.+ ( 14 nos × 0.583 × 0.75 × 0.75) } ]

= [140 cu ft - 91.31 cu ft.]

=48.69 cu ft.


The total volume of backfilling 

= backfilling for plinth beam + backfilling for footing 

= 36.412 cu ft. + 48.69 cu ft.

= 85.102 cu ft. i.e. 2.409 cum.

BACK πŸ‘ˆ PART 6                  CONTINUED πŸ‘‰PART 8

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