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Estimating block masonry of compound wall. / Estimating & costing of a compound wall ( part 6 ).

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Let us build this compound wall of 6" thickness having 6 ft. height as shown in the drawing.




Plan of the compound wall.


The total length of the compound wall 

     = site perimeter - gate length

     = (40ft. × 2 nos.) + (30 ft. × 2 nos.) - 10 ft.

     = 80 ft. + 60 ft. -10 ft.

     = 130 ft. 


The total length of the block masonry

      = compound wall length - (no. of columns × width of a single column.)

     = 130 ft. - (14 nos.× 0.75 ft.)

     = 130 ft. - 10.5 ft.

     = 119.5 ft.


Height of the block masonry

   = compound wall height - coping thickness

   = 6 ft - 0.33 ft.

  = 5.67 ft.


7. The volume of the block masonry

   = length × height × thickness 

   = 119.5 ft. × 5.67 ft. × 0.5 ft.

   = 338.7825 cu ft.


Number of concrete blocks required

   = 210 nos. × ( 338.78 cu ft. ÷ 100 cu ft.)

   = 712 nos.


The number of cement bags required

   = 1.038 bags × ( 338.78 cu ft. ÷ 100 cu ft.)

   =3.516 bags.


The volume of sand required

   = 7.634 cu ft. × ( 338.78 cu ft. ÷ 100 cu ft.)

  = 25.86 cu ft.

Note: The above-given quantity is taken from the article "Calculating the quantity of materials in a 100 cubic ft. block wall."

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