All about civil construction knowledge- PARAM VISIONS

Calculating the quantity of cement, sand, & aggregates in M10 (1:3:6) grade PCC./Rate analysis of PCC.

 Let us consider M10 grade PCC as shown in the below drawing for the calculation purpose.


Given data:

The grade of PCC = M10.

Length of the PCC bed = 4m.

Breadth of the PCC  = 2.5m.

The thickness of the PCC = 100mm. = 0.01m.


The volume of the PCC bed

= length × breadth × thickness

= 4m. × 2.5m. × 0.01m.

= 1 CUM.

Here, 

Cement:sand: aggregates = 1:3:6 (a:b:c)

M10 grade means 👉  1:3:6 ratio.

Wet volume of PCC = 1 cum.


Now, dry volume of PCC 

                 = 1.54 × wet volume of concrete.

                = 1.54 × 1 cum = 1.54 cum.

              

1. Volume of  cement required

   = [{its ratio  ÷ (total ratio)} × dry volume of PCC.]

    =[{ a ÷ (a + b + c)} × dry volume of PCC.]

   = [{1÷ ( 1 + 3 +6 )} × 1.54]

   = [{ 1 ÷ 10 } × 1.54]

   = [0.1 × 1.54]

   =  0.154 cum.

As you know, 1 bag of cement = 0.03472 cum.

So, the number of cement bags required

       = 0.154 cum. ÷ 0.03472 cum.

       = 4.435 bags  


Weight of cement 

= 4.435 bags × 50 kgs.

(1 bag of cement = 50 kgs.)

221.77 kgs.


2. Volume of sand required

     = [{its ratio  ÷ (total ratio)} × dry volume of PCC.]

    =[{ b ÷ (a + b + c)} × dry volume of PCC.]

   = [{3÷ ( 1 + 3 +6 )} × 1.54]

   = [{3 ÷ 10 } × 1.54]

   = [0.3 × 1.54]

   =  0.462 cum.

  =  16.32 cu ft.


3. Volume of aggregates required

     = [{its ratio  ÷ (total ratio)} × dry volume of PCC.]

    =[{ c ÷ (a + b + c)} × dry volume of PCC.]

   = [{6÷ ( 1 + 3 +6 )} × 1.54]

   = [{ 6 ÷ 10 } × 1.54]

   = [0.6 × 1.54]

   =  0.924 cum.

   = 32.63 cu ft.


4. Volume of water required.

  Let us consider the w/c ratio for M10 grade concrete as 0.5.

i.e. wt. of cement / wt. of water = 0.5

 So, the weight. of water 

       = 0.5 × wt. of cement 

       =0.5 × 221.77 kgs

      = 110.89 kgs

     = 110.89 liters 

      ( 1kg= 1 liter)

Note: This w/c ratio holds good if you use plasticizers. Practically for good workability, the water we add for the concrete is 133 liters.


Alternate method:

1. Volume of cement ( from above) = 0.154 cum.


2. Volume of sand     

         = [volume of cement × b]

         =   [0.154 cum × 3]

         = 0.462 cum.


3.  Volume of aggregates

      = [volume of cement × c]

      = [ 0.154 cum × 6]

      = 0.924 cum.

Now, let us put these material quantities in a table format for easy reference.

          Materials in 1CUM of M10 grade PCC.

Sl. No.

Item

 Unit

In cum.

In cu ft.

1.

Cement

bags

4.435 bags

-

2.

Sand

-

0.462

16.32

3.

Aggregates

-

0.924

32.63

4.

Water

litres

110.89

-

 

Note: To calculate the quantity of materials in M7.5 & M15 grade PCC, you have to replace the mix ratio in the above calculation.
Share:

No comments:

Post a Comment

Please do not enter any spam link in the comment box

Translate

Blog Archive

popular posts

Google search

Recent Posts

Pages