Calculating the quantity of cement, sand, & aggregates in M10 (1:3:6) grade PCC./Rate analysis of PCC.

 Let us consider M10 grade PCC as shown in the below drawing for calculation purposes.

Given data:

The grade of PCC = M10.

Length of the PCC bed = 4m.

Breadth of the PCC  = 2.5m.

The thickness of the PCC = 100mm. = 0.01m.

The volume of the PCC bed

= length × breadth × thickness

= 4m. × 2.5m. × 0.01m.

= 1 CUM.

Here, 

Cement:sand: aggregates = 1:3:6 (a:b:c)

M10 grade means 👉  1:3:6 ratio.

Wet volume of PCC = 1 cum.

Now, the dry volume of PCC 

                 = 1.54 × wet volume of concrete.

                = 1.54 × 1 cum = 1.54 cum.

              

1. Volume of  cement required

   = [{its ratio  ÷ (total ratio)} × dry volume of PCC.]

    =[{ a ÷ (a + b + c)} × dry volume of PCC.]

   = [{1÷ ( 1 + 3 +6 )} × 1.54]

   = [{ 1 ÷ 10 } × 1.54]

   = [0.1 × 1.54]

   =  0.154 cum.

As you know, 1 bag of cement = 0.03472 cum.

So, the number of cement bags required

       = 0.154 cum. ÷ 0.03472 cum.

       = 4.435 bags  

Weight of cement 

= 4.435 bags × 50 kgs.

(1 bag of cement = 50 kgs.)

= 221.77 kgs.

2. Volume of sand required

     = [{its ratio  ÷ (total ratio)} × dry volume of PCC.]

    =[{ b ÷ (a + b + c)} × dry volume of PCC.]

   = [{3÷ ( 1 + 3 +6 )} × 1.54]

   = [{3 ÷ 10 } × 1.54]

   = [0.3 × 1.54]

   =  0.462 cum.

  =  16.32 cu ft.

3. Volume of aggregates required

     = [{its ratio  ÷ (total ratio)} × dry volume of PCC.]

    =[{ c ÷ (a + b + c)} × dry volume of PCC.]

   = [{6÷ ( 1 + 3 +6 )} × 1.54]

   = [{ 6 ÷ 10 } × 1.54]

   = [0.6 × 1.54]

   =  0.924 cum.

   = 32.63 cu ft.

4. Volume of water required.

  Let us consider the w/c ratio for M10 grade concrete as 0.5.

i.e. wt. of cement / wt. of water = 0.5

 So, the weight. of water 

       = 0.5 × wt. of cement 

       =0.5 × 221.77 kgs

      = 110.89 kgs

     = 110.89 liters 

      ( 1kg= 1 liter)

Note: This w/c ratio holds good if you use plasticizers. Practically for good workability, the water we add for the concrete is 133 liters.

Alternate method:

1. Volume of cement ( from above) = 0.154 cum.

2. Volume of sand     

         = [volume of cement × b]

         =   [0.154 cum × 3]

         = 0.462 cum.

3.  Volume of aggregates

      = [volume of cement × c]

      = [ 0.154 cum × 6]

      = 0.924 cum.

Now, let us put these material quantities in a table format for easy reference.

Materials in 1CUM of M10 grade PCC.
Sl. No.	Item	Unit	In cum.	In cu ft.
1.	Cement	bags	4.435 bags	-
2.	Sand	-	0.462	16.32
3.	Aggregates	-	0.924	32.63
4.	Water	litres	110.89	-

 

Note: To calculate the quantity of materials in M7.5 & M15 grade PCC, you have to replace the mix ratio in the above calculation.

To go through all types of quantity estimate articles, click here.

Thank you for going through these calculation steps❤. Have a good day 😄.

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