### How to calculate the materials required for 9" brickworks?/ Brick, cement, & sand calculations for brick wall masonry.

Let us consider a 9" brick wall of size 10 ft. × 13.333 ft.× 0.75 ft. (9")  as shown in the drawing.

Now, we will build this wall with a conventional brick of size 9 inches × 4 inches × 3 inches as shown in the image below.

Given data:

Length of the brick wall = 13' 4" = 13.333 ft.

Height of the brick wall = 10 ft.

The thickness of the brick wall = 9" = 0.75 ft.

Brick size = 9 inches × 4 inches × 3 inches

Mortar thickness = 10mm = 0.39 inches

To calculate the number of bricks required to build this wall, first, we will find out the volume of the wall and the volume of a single brick with or without mortar.

The volume of the brick wall

= Length × Height × Thickness

= 10 ft. × 13.333 ft. × 0.75 ft.

= 100 cu ft.

Now, the volume of the brick

= length × height × thickness

= 9 inches × 3 inches × 4 inches

( By converting them into ft.)

= 0.75 ft. × 0.25 ft. × 0.333 ft.

=0.0625 cu ft.

From the drawing given below, you can observe that the addition of the mortar thickness comes on the 3 sides of every brick. I have denoted them with the nos. 1, 2, & 3.

So, the volume of the brick with mortar

= 9.39 inches  ×3.39 inches  × 4.39 inches

=139.743 cubic inches.

=0.0809 cu ft.

1.  The number of bricks required

= volume of the wall ÷ volume of the brick with mortar

= 100 cu ft. ÷ 0.0809 cu ft.

=1236 nos.

The volume of mortar required

= [volume of the brick wall - the volume of the total no. of bricks]

= [100 cu ft. - (1236 nos. × 0.0625 cu ft.)]

=   [100 cu ft. - 77.25 cu ft.]

=22.75 cu ft.

Let us prepare this 22.75 cu ft. of mortar in a 1: 6 ratio to build this 100 cu ft. of the brick wall.

Dry volume of the cement mortar

= 1.33 × 22.75

= 30.258 cu ft.

2.  Volume of the sand

= (6  ÷ ( 6 + 1)) × 30.258

= 0.8571 × 30.258

= 25.934 cu ft.

3. Volume of the cement

= total dry mortar vol. - volume of sand

= 30.258 cu ft. - 25.934 cu ft.

=4.324 cu ft.

As you know, one bag of cement = 1.226 cu ft.

Number of cement bags

= 4.324 cu ft. ÷ 1.226 cu ft.

=   3.527bags.

Let us now find out the materials required for 1 cu ft. & 1 CUM of  9" brick wall.

1. Bricks:

Bricks required for 1 cu ft. of brick wall

= 1236 nos. ÷ 100

12.36 nos.

Bricks required for 1 CUM of brick wall

= 12.36nos. × 35.315

436.5 nos.

2. Cement:

Cement required for 1 cu ft. of brick wall

= 3.527 bags. ÷ 100

0.0353 bags.

Cement required for 1 CUM of brick wall

= 0.0353 bags × 35.315

1.247 bags.

3. Sand:

Sand required for 1 cu ft. of brick wall

= 25.934 cu ft. ÷ 100

0.2593 cu ft.

Sand required for 1 CUM of brick wall

= 0.2593 cu ft. × 35.315

9.157 cu ft.

Continued 👉 Rate analysis of 9"  thick brick wall work.

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