All about civil construction knowledge- PARAM VISIONS

How to calculate the materials required for 9" brickworks?/ Brick, cement, & sand calculations for brick wall masonry.

 Let us consider a 9" brick wall of size 10 ft. × 13.333 ft.× 0.75 ft. (9")  as shown in the drawing.




Now, we will build this wall with a conventional brick of size 9 inches × 4 inches × 3 inches as shown in the image below.




Given data:

Length of the brick wall = 13' 4" = 13.333 ft.

Height of the brick wall = 10 ft.

The thickness of the brick wall = 9" = 0.75 ft.

Brick size = 9 inches × 4 inches × 3 inches

Mortar thickness = 10mm = 0.39 inches



To calculate the number of bricks required to build this wall, first, we will find out the volume of the wall and the volume of a single brick with or without mortar.

The volume of the brick wall 

                  = Length × Height × Thickness 

                  = 10 ft. × 13.333 ft. × 0.75 ft.

                  = 100 cu ft.

Now, the volume of the brick

                 = length × height × thickness

                 = 9 inches × 3 inches × 4 inches 

                    ( By converting them into ft.)

                 = 0.75 ft. × 0.25 ft. × 0.333 ft.
 
                 =0.0625 cu ft.


From the drawing given below, you can observe that the addition of the mortar thickness comes on the 3 sides of every brick. I have denoted them with the nos. 1, 2, & 3.



So, the volume of the brick with mortar

                     = 9.39 inches  ×3.39 inches  × 4.39 inches

                     =139.743 cubic inches.

                     =0.0809 cu ft.

 

1.  The number of bricks required

                  = volume of the wall ÷ volume of the brick with mortar

                  = 100 cu ft. ÷ 0.0809 cu ft.

                  =1236 nos.


The volume of mortar required 

        = [volume of the brick wall - the volume of the total no. of bricks]

        = [100 cu ft. - (1236 nos. × 0.0625 cu ft.)]

        =   [100 cu ft. - 77.25 cu ft.]

           =22.75 cu ft.


Let us prepare this 22.75 cu ft. of mortar in a 1: 6 ratio to build this 100 cu ft. of the brick wall.

Dry volume of the cement mortar

           = 1.33 × wet volume of the mortar.

          = 1.33 × 22.75

           = 30.258 cu ft.


   2.  Volume of the sand

          = (6  ÷ ( 6 + 1)) × 30.258

           = 0.8571 × 30.258

            = 25.934 cu ft. 


3. Volume of the cement 

   = total dry mortar vol. - volume of sand

    = 30.258 cu ft. - 25.934 cu ft.

    =4.324 cu ft.

As you know, one bag of cement = 1.226 cu ft.

  Number of cement bags 

    = 4.324 cu ft. ÷ 1.226 cu ft.

    =   3.527bags.


Let us now find out the materials required for 1 cu ft. & 1 CUM of  9" brick wall.

1. Bricks:

Bricks required for 1 cu ft. of brick wall

= 1236 nos. ÷ 100 

12.36 nos.


Bricks required for 1 CUM of brick wall

= 12.36nos. × 35.315

436.5 nos.


2. Cement:

Cement required for 1 cu ft. of brick wall

= 3.527 bags. ÷ 100

0.0353 bags.

Cement required for 1 CUM of brick wall

= 0.0353 bags × 35.315

1.247 bags.


3. Sand:

Sand required for 1 cu ft. of brick wall

= 25.934 cu ft. ÷ 100

0.2593 cu ft.


Sand required for 1 CUM of brick wall

= 0.2593 cu ft. × 35.315

9.157 cu ft.

Continued 👉 Rate analysis of 9"  thick brick wall work.

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