PARAM VISIONS

All about civil construction knowledge- PARAM VISIONS

How to calculate the active earth pressure on a retaining wall?

Eg:

Determine active earth pressure on the retaining wall as shown in the below drawing.

Consider πw = 10KN/m³.

Given data:

Depth of 1st layer = H1 = 3m.

The angle of friction = π±1 = 34°

Unit weight = π = 16KN/m³

Depth of 2nd layer =H2 = 3m.

The angle of friction = π±2 = 39°

Saturated unit weight = πsat = 18KN/m³.

Calculation:

Coefficient of earth pressure for 1st layer

Ka1 = [1-sinπ±1 / 1+ sinπ±1]

=  [(1-sin34°) / (1+ sin34°)]

= [(1-0.5592) / (1+ 0.5592)]

= [0.4408/1.5592]

Ka1 = 0.283

Coefficient of earth pressure for 2nd layer

Ka2 = [1-sinπ±2 / 1+ sinπ±2]

=  [(1-sin39°) / 1+ (sin39°)1]

= [(1-0.6293) / (1+ 0.6293)]

= [0.3706/1.6293]

Ka2 = 0.228

Intensity of pressure at layer B

p1 = [ Ka1 x π xH1]

= [ 0.283 x 16 x 3]

p1 = 13.584KN/m².

Intensity of pressure at layer C due to 1st layer

p2 =  [ Ka2 x π xH1]

= [ 0.228 x 16 x 3]

p2 = 10.944KN/m².

The intensity of pressure at layer C due to 2nd layer

p3 =  [ Ka2 x π¹ xH2]

Where π¹ = submerged unit wt.

= [πsat -πw]

= [18 - 10]

= 8KN/m³.

p3   = [ 0.228 x 8 x 3]

= 5.472KN/m².

Pressure due to water

u = [πw x H2]

= [10 x 3]

u = 30KN/m².

Note: The pr. due to water in the 1st layer will be 0, as the water table is only in the 2nd layer.

Now, let us draw the pressure distribution diagram from the above-calculated values.

Total pressure of triangle ABD

P1= [1/2 x base x height]

= [1/2 x 13.584 x 3]

P1= 20.376KN.

Total pressure of rectangle BCFE

P2= [Base x height]

= [10.944 x 3]

P2= 32.83KN.

The total pressure of triangle EFG

P3= [1/2 x 5.472 x 3]

P3= 8.208KN.

The total pressure of the triangle EGH

P4= [1/2 x 30 x 3]

P4= 45KN.

The total active earth pressure

P = [P1 + P2 + P3 + P4]

= [20.376 + 32.83 + 8.208 + 45]

P = 106.414KN.

Thank you for going through these calculation steps. Have a good day π.