Eg:
The unit cohesion of soil is 12KN/m² normal stress is 22KN/m². & the angle of internal friction is 32°. Calculate the shear strength of the soil.
Given data:
The cohesion of soil = C = 12KN/m².
Normal stress = π = 22KN/m².
The angle of internal friction = π± = 32°
To find:
Shear strength of soil = π½ =?
Calculation:
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Shear strength of soil is calculated by the formula
π½ = [C + (π tanπ±)]
= [12 + (22✖ tan32°)]
= [ 12 + (22✖ 0.6248)]
= [12 + 13.747]
π½ = 25.747 KN/m².
Thank you for going through these calculation steps❤. Have a good day π.
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