### How to calculate the load transfer from a slab to the beam?/Calculating the load over the beam from a one-way slab.

Let us calculate the total load over the beams B1 & B2 as shown below.

Given data:

Span of beam B1= 5500mm. = 5.5m.

Span of beam B2 = 2500mm. = 2.5m.

Sectional dimension of all the beams = 230mm. x 450mm. = 0.23m. x 0.45m.

Calculation:

Lx /Ly = 5500mm. / 2500mm.

= 2.2 > 2.

Therefore it is a one-way slab.

The load distribution of one-way slab over the beams are as shown below.

1. Beam - B1:

Total load over the beam B1

= [Self wt. of the beam + superimposed load from the slab]

Here,

a.) Self wt. of the beam /m.

= [(area of cross-section) × density of RCC]

= [ (0.23m. x 0.45m.) × 25 KN/m³]

2.588 KN/m.

Total self-wt. of the beam

= [ beam wt./m × span of the beam]

= [2.588KN/m × 5.5m.]

14.234 KN.

Factored self-wt. of the beam

= [1.5 × 14.234]

= 21.351KN.

b.) Load transferred from slab to the beam B1

= [1/2 x (area of slab) x W]

Before proceeding further, Go through the article 👇

Where all the load distribution formula is derived.

= [ 1/2 x (5.5  x 2.5) x 12.94]

The value of is taken from the article

How to calculate the total load over the RCC slab?

= 88.96KN.

Total factored load over the beam B1

= [Factored self wt. of the beam + factored load from the slab]

= [21.351 + 88.96]

110.311KN.

2. Beam - B2:

Total load over the beam B2

= [Self wt. of the beam]

Here,

a.) Self wt. of the beam

= [(area of cross-section) × density of RCC]

= [ (0.23m. x 0.45m.) × 25 KN/m³]

2.588 KN/m.

Factored self wt. of the beam

= [1.5 × 2.588KN/m.]

3.88 KN/m.

Total factored self-wt. of the beam

= [ factored wt./m × span of the beam]

= [3.88KN/m × 2.5m.]

9.70 KN.

Total factored load over the beam B2

= 9.70KN.

Note: Beam-B2 does not carry any load from the slab.

Thank you for going through these calculation steps. Have a good day 😄.