Let us calculate the total load over beams B1 & B2 as shown below.
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Given data:
A span of beam B1= 4500mm. = 4.5m.
Span of beam B2 = 3000mm. = 3.0m.
Sectional dimension of all the beams = 230mm. x 450mm. = 0.23m. x 0.45m.
Calculation:
Lx /Ly = 4500mm. / 3000mm.
= 1.5 < 2.
Therefore it is a two-way slab.
The load distribution of the 2-way slab over the beams is as shown below.
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1. Beam - B1:
Total load over the beam B1
= [Self wt. of the beam + superimposed load from the slab]
Here,
a.) Self wt. of the beam
= [(area of cross-section) × density of RCC]
= [ (0.23m. x 0.45m.) × 25 KN/m³]
= 2.588 KN/m.
Factored self wt. of the beam
= [1.5 × 2.588KN/m.]
= 3.88 KN/m.
Total factored self-wt. of the beam
= [ factored wt./m × span of the beam]
= [3.88KN/m × 4.5m.]
= 17.46 KN.
b.) Load transferred from slab to the beam B1
= [1/2 × ( Lx Ly - Lx²/2) × W]
Before proceeding further, Go through the article 👇
👀. Understanding the concept of the load distribution from slab to beam.
Where all the load distribution formula is derived
= [1/2 × ( 3 × 4.5 - 3²/2) × 12.94]
The value of W is taken from the article
How to calculate the total load over the RCC slab?
= [ 1/2 × ( 9 ) × 12.94]
= 58.23KN.
Total factored load over the beam B1
= [Self wt. of the beam + load from the slab]
= [ 17.46 + 58.23]
= 75.69 KN.
2. Beam - B2:
Total load over the beam B2
= [Self wt. of the beam + superimposed load from the slab]
Here,
a.) Self wt. of the beam
= [(area of cross-section) × density of RCC]
= [ (0.23m. x 0.45m.) × 25 KN/m³]
= 2.588 KN/m.
Factored self wt. of the beam
= [1.5 × 2.588KN/m.]
= 3.88 KN/m.
Total factored self-wt. of the beam
= [ factored wt./m × span of the beam]
= [3.88KN/m × 3m.]
= 11.64 KN.
b.) Load transferred from slab to the beam B2
= [ (Lx²/4) x W]
= [ (3²/4) x 12.94]
= [2.25 x 12.94]
= 29.11KN.
Total factored load over the beam B2
= [Self wt. of the beam + load from the slab]
= [ 11.64 + 29.11]
= 40.755 KN.
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Thank you for going through these calculation steps❤. Have a good day 😄.
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