# PARAM VISIONS

All about civil construction knowledge- PARAM VISIONS

### How to calculate the materials required for 4" brickworks?/ Brick, cement, & sand calculations for single brick wall.

Let us consider a single brick wall of size 10ft × 30ft.× 0.333 ft. (4")  as shown in the drawing.

Now, we will build this wall with a conventional brick of size 9 inches × 4 inches × 3 inches as shown in the image below.

Given data:

Length of the brick wall = 30 ft.

Height of the brick wall = 10 ft.

The thickness of the brick wall = 0.333 ft.

Brick size = 9 inches × 4 inches × 3 inches

Mortar thickness = 10mm = 0.39 inches

To calculate the number of bricks required to build this wall, first, we will find out the volume of the wall and the volume of a single brick with or without mortar.

The volume of the brick wall

= Length × Height × Thickness

= 10ft × 30ft × 0.333 ft.

= 100cu ft.

Now, the volume of the brick

= l × h × t

= 9 inches × 3 inches × 4 inches

( By converting them into ft.)

= 0.75ft × 0.25 ft × 0.333 ft.

=0.0625 cu ft.

From the drawing given below, you can observe that the addition of the mortar thickness comes on the 2 sides of every brick.

So, the volume of the brick with mortar

= 9.39 inches  ×3.39 inches  × 4 inches

=127.3284 cubic inch.

=0.0737cu ft.

1.  The number of bricks required

= volume of the wall ÷ volume of the brick with mortar

= 100 cu ft. ÷ 0.0737 cu ft.

=1357 nos.

The volume of mortar required

= volume of the brick wall - the volume of the total no. of bricks

= 100 cu.ft. - (1357 nos. × 0.0625 cu.ft.)

=   100 cu ft. - 84.812 cu ft.

=15.187 cu ft.

Let us prepare this 15.187 cu ft. of mortar in a 1: 6 ratio to build this 100 cu ft. of the brick wall.

Dry volume of the cement mortar

= 1.33 × 15.187

= 20.198 cu ft.

2.  Volume of the sand

= (6  ÷ ( 6 + 1)) × 20.198

= 0.8571 × 20.198

= 17.312 cu ft.

3. Volume of the cement

= total dry mortar vol. - volume of sand

= 20.198 cu ft - 17.312 cu ft.

=2.886 cu ft.

As you know, one bag of cement = 1.226 cu ft.

Number of cement bags

= 2.886 cu ft. ÷ 1.226 cu ft.

=   2.354bags.

Let us now find out the materials required for 1 cu ft. & 1 CUM. of  4" brick wall.

1. Bricks:

Bricks required for 1 cu ft. of brick wall

= 1357 nos. ÷ 100

= 13.57 nos.

Bricks required for 1 CUM of brick wall

= 13.57nos. × 35.315

= 479 nos.

2. Cement:

Cement required for 1 cu ft. of brick wall

= 2.354 bags. ÷ 100

= 0.0235 bags.

Cement required for 1 CUM of brick wall

= 0.0235 bags × 35.315

= 0.83 bags.

3. Sand:

Sand required for 1 cu ft. of brick wall

= 17.312 cu ft. ÷ 100

= 0.1731 cu ft.

Sand required for 1 CUM of brick wall

= 0.1731 cu ft. × 35.315

= 6.11 cu ft.

#### 1 comment:

1. Moos & Unkraut professionell entfernen lassen Wow, cool post. I'd like to write like this too - taking time and real hard work to make a great article... but I put things off too much and never seem to get started. Thanks though.

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