All about civil construction knowledge- PARAM VISIONS

How to calculate the materials required for 4" brickworks?/ Brick, cement, & sand calculations for single brick wall.

Let us consider a single brick wall of size 10ft × 30ft.× 0.333 ft. (4")  as shown in the drawing.





Now, we will build this wall with a conventional brick of size 9 inches × 4 inches × 3 inches as shown in the image below.

Given data:

Length of the brick wall = 30 ft.

Height of the brick wall = 10 ft.

The thickness of the brick wall = 0.333 ft.

Brick size = 9 inches × 4 inches × 3 inches

Mortar thickness = 10mm = 0.39 inches



To calculate the number of bricks required to build this wall, first, we will find out the volume of the wall and the volume of a single brick with or without mortar.

The volume of the brick wall 

                  = Length × Height × Thickness 

                  = 10ft × 30ft × 0.333 ft.

                  = 100cu ft.

Now, the volume of the brick

                 = l × h × t

                 = 9 inches × 3 inches × 4 inches 

                    ( By converting them into ft.)

                 = 0.75ft × 0.25 ft × 0.333 ft.
 
                 =0.0625 cu ft.


From the drawing given below, you can observe that the addition of the mortar thickness comes on the 2 sides of every brick.


So, the volume of the brick with mortar

                     = 9.39 inches  ×3.39 inches  × 4 inches

                     =127.3284 cubic inch.

                     =0.0737cu ft.

 

1.  The number of bricks required

                  = volume of the wall ÷ volume of the brick with mortar

                  = 100 cu ft. ÷ 0.0737 cu ft.

                  =1357 nos.


The volume of mortar required 

        = volume of the brick wall - the volume of the total no. of bricks 

        = 100 cu.ft. - (1357 nos. × 0.0625 cu.ft.)

        =   100 cu ft. - 84.812 cu ft.

           =15.187 cu ft.


Let us prepare this 15.187 cu ft. of mortar in a 1: 6 ratio to build this 100 cu ft. of the brick wall.

Dry volume of the cement mortar

           = 1.33 × wet volume of the mortar.

          = 1.33 × 15.187

           = 20.198 cu ft.


   2.  Volume of the sand

          = (6  ÷ ( 6 + 1)) × 20.198

           = 0.8571 × 20.198

            = 17.312 cu ft. 


3. Volume of the cement 

   = total dry mortar vol. - volume of sand

    = 20.198 cu ft - 17.312 cu ft.

    =2.886 cu ft.

As you know, one bag of cement = 1.226 cu ft.

  Number of cement bags 

    = 2.886 cu ft. ÷ 1.226 cu ft.

    =   2.354bags.


Let us now find out the materials required for 1 cu ft. & 1 CUM. of  4" brick wall.

1. Bricks:

Bricks required for 1 cu ft. of brick wall

= 1357 nos. ÷ 100 

= 13.57 nos.


Bricks required for 1 CUM of brick wall

= 13.57nos. × 35.315

= 479 nos.


2. Cement:

Cement required for 1 cu ft. of brick wall

= 2.354 bags. ÷ 100

= 0.0235 bags.

Cement required for 1 CUM of brick wall

= 0.0235 bags × 35.315

= 0.83 bags.


3. Sand:

Sand required for 1 cu ft. of brick wall

= 17.312 cu ft. ÷ 100

= 0.1731 cu ft.


Sand required for 1 CUM of brick wall

= 0.1731 cu ft. × 35.315

= 6.11 cu ft.

     Continued 👉   What will be the cost of single (4") brick wall masonry?/ Rate analysis of 4" brick wall.


Share:

No comments:

Post a Comment

Please do not enter any spam link in the comment box

Translate

Google search

popular posts

Pages

Recent Posts